An electron moving to the right at 7.5 x 10^5 m/s enters a uniform electric field parallel to its direction of motion. if the electron is to be brought to rest in the space of 7.0 cm . what is the strength of the field?

The strength of the field is 22.84 N/C.

Explanation:

Given that,

Speed

Distance = 7.0 cm

We need to calculate the acceleration

Using equation of motion

Put the value in the equation

We need to calculate the strength of the field

Using newton's second law and electric force

Put the value into the formula

Hence, The strength of the field is 22.84 N/C.

ok

explanation:

your answer is c! hope this : )