An electron with speed 2.45 x 10^7 m/s is traveling parallel to a uniform electric field of magnitude 1.18 x 10^4n/c . how much time will elapse before it returns to its starting point?

time will elapse before it return to  its staring point is 23.6 ns

Explanation:

given data

speed u = 2.45 × m/s

uniform electric field E = 1.18 × N/C

to find out

How much time will elapse before it returns to its starting point

solution

we find acceleration first by electrostatic force that is

F = Eq

here

F = ma by newton law

so

ma = Eq

here m is mass , a is acceleration and E is uniform electric field and q is charge of electron

so

put here all value

9.11 × kg ×a = 1.18 × × 1.602 ×

a = 20.75 × m/s²

so acceleration is 20.75 × m/s²

and

time required by electron before come rest is

use equation of motion

v = u + at

here v is zero and u is speed given and t is time so put all value

2.45 × = 0 + 20.75 × (t)

t = 11.80 × s

so time will elapse before it return to  its staring point is

time = 2t

time = 2 ×11.80 ×

time is 23.6 × s

time will elapse before it return to  its staring point is 23.6 ns

hi there if you are asking for conformation that wavelingth is the correct answer is wrong it is the answer is frequency. : )

i hope this you out, have a wonderful day

mistakes are ok