If the potential due to a point charge is 500 v at a distance of 15.0 m, what are the sign and magnitude of the charge?

Explanation:

The potential V due to a charge q,  at a distance r, is:

k=8.99×109 N·m^2/C^2      :Coulomb constant

We replace the values in order to find q:

the rearrangement of particles in a physical change. hope this