The maximum mass that can be hung verti from a string without breaking the string is to ke. a length of this string that is 2 m long is used to rotate a 0.5 kg object in a circle on a frictionless table with the string horizontal. the maximum speed that the mass can attain under these conditions without the string breaking is most nearly (a) 5 m/s (b) 10 m/s (c) 14 m/s (d) 20 m/s (e) 100 m/s .: s

Explanation:

The maximum mass that can be hung from a string, m = 10 kg

Length of the string, l = 2 m

Mass of the object, m = 0.5 kg

Let v is the maximum speed that the mass can attain under these conditions without the string breaking. If T is the maximum tension in the string. So,

The centripetal force is provided by the tension in the string such that :

v = 19.79 m/s

or

v = 20 m/s

So, the maximum speed that the mass can attain under these conditions without the string breaking is 20 m/s. Hence, this is the required solution.

its a 5.5 n

glad that

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2