An irregular object of mass 3 kg rotates about an axis, about which it has a radius of gyration of 0.2 m, with an angular acceleration of 0.5 rad. s? . the magnitude of the applied torque is: a) 0.30 n. m b) 3.0 x 102 n. m c) 0.15 n. m d) 7.5 x 102 n. m e) 6.0 x 102 n. m.

0.06 Nm

Explanation:

mass of object, m = 3 kg

radius of gyration, k = 0.2 m

angular acceleration, α = 0.5 rad/s^2

Moment of inertia of the object

I = 3 x 0.2 x 0.2 = 0.12 kg m^2

The relaton between the torque and teh moment off inertia is

τ = I α

Wheree, τ is torque and α be the angular acceleration and I be the moemnt of inertia

τ = 0.12 x 0.5 = 0.06 Nm

explanation:

newton's third law, for every action there is an equal and opposite reaction.