The driver of a pick up truck going 100 km/h applies the brakes, giving the truck a form deceleration of 6.50 m/s^2 while it travels 20.0 m. what is the speed of the truck in km/h at the end of this distance?

81.42 km/h

Explanation:

t = Time taken for the car to slow down

u = Initial velocity = 100 km/h

v = Final velocity

s = Displacement = 20 m = 0.02 km

a = Acceleration = -6.5 m/s² = -0.0065×60×60×60×60 = -84240 km/h²

Equation of motion

Speed of the truck at the end of this distance is 81.42 km/h

found in the nucleus

has mass of one amu

answer: (431,2)

step-by-step explanation: