Calculate the speed of a proton that has moved in a uniform electric field of 180.0 n/c from rest over a distance of 12.5-cm. assume it began at rest.

Given:

Electric field = 180 N/C

Let the speed of proton be "x"

x =

the velocity of the proton is 65574.38 m/s

Explanation:

given,

uniform electric field = 180 N/C

Distance = 12.5 cm = 0.125 m

charge of proton = 1.6 × 10⁻¹⁹ C

force = E × q

         =180 ×  1.6 × 10⁻¹⁹

        F= 2.88 × 10⁻¹⁷ N

mass of proton = 1.673 × 10⁻²⁷ kg

acceleration =

                     =

                     =1.72 × 10¹⁰ m/s²

velocity =

             =65574.38 m/s

hence , the velocity of the proton is 65574.38 m/s

report!

explanation:

physics means: "the branch of science concerned with the nature and properties of matter and energy. the subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms."

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.