Acharge of 9 µc is on the y axis at 1 cm, and a second charge of −9 µc is on the y axis at −1 cm. find the force on a charge of 7 µc on the x axis at x = 6 cm. the value of the coulomb constant is 8.98755 × 10^9 n*m^2/c^2. answer in n units of n.

The net force on X is Fx=75.4N

The net force on Y is FY=25.17N

Explanation:

This is an electrostatic problem, we can calculate de force applying the formula:

the force because of charge at 1cm on the X axis, will only have an X component of force, so:

For the force because of the charge of the Y axis we have to find the distances usign pitagoras, and the angle:

we can find the angle with:

We now can calculate the force of the X axis because of the second charge:

and for the Force on Y axis:

The net force on X axis is:

Fx=226.48N-151.08N=75.4N

Fy=-25.17N

The magnitude of the resultant force is equal to 0.0216 N

The direction is along the negative y axis

Explanation:

According to the exercise data:

q1 = 9x10^-6 C (0,1)

q2 = -9x10^-6 C (0,-1)

q = 7x10^6 C (6,0)

the distance between load q1 and load q will be equal to:

The same way to calculate the distance between q2 and q:

The force on q due to the load q1, is calculated with the following equation:

The same way to force F2:

F2 = (8.987559x10^9*-9x10^-6*7x10^-6))/(6.08^2)*(cos45i-sin45j) = 0.0108 N(i-j)

The resultant force:

F = F1 + F2 = 0.0108 N *(-2j) = - 0.0216 N j

The magnitude is equal to 0.0216 N

The direction is along the negative y axis

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vapour or gas assuming atmospheriv pressure