![11-20=\int_{0}^{3}(cx-3x^{2})\cdot dx\\\\-9=[\frac{cx^2}{2}]_0^3-[\frac{3x^3}{3}]_0^3\\\\-9=\frac{9c}{2}-27\\\\4.5c=18\\\\\therefore c=4](/tpl/images/0230/7626/41dad.png)
Aforce f=(cx-3.00x2)i acts on a partical as theparticle
moves along an x axis, with f in newto...
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