Arocket is fired at a speed of 75.0 m/s from ground level, at an angle of 60.0° above the horizontal. the rocket is fired toward an 11-0m-high wall, which is located 27.0 m away. the rocket attains its launch speed in a negligibly short period of time, after which its engines shut down and the rocket coasts. by how much does the rocket clear the top of the wall?

ΔH = 33.17m

Explanation:

By knowing the amount of time it takes the rocket to travel the horizontal 27m, we will be able to calculate the height when x=27m. So:

  where

Solving for t:

t=0.72s

Now we calculate the height of the rocket:

If the wall was 11m-high, the difference is:

ΔH = 33.17m

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.