Abead with a mass of 0.050 g and a charge of 20 nc is free to slide on a vertical rod. at the base of the rod is a fixed 20 nc charge. in equilibrium, at what height above the fixed charge does the bead rest?

height above the fixed charge is 8.571 cm

Explanation:

given data

mass m = 0.050 g = 5 × kg

charge bead q1 = 20 nC = 20 × C

charge base q2 = 20 nC = 20× C

to find out

what height above the fixed charge does the bead rest

solution

we know that when charge at rest then downward gravitational force is balance by electrostatic force so

  .............1

here k is 9 × Nm²/C² and g = 9.8 m/s² and r is height of bread  

put here all value in equation 1

r² = 7.3469 ×

r = 0.08571 m = 8.571 cm

so height above the fixed charge is 8.571 cm

what is the actual question though?