Vector a is in the direction 44.0 degrees clockwise from the y-axis. the x-component of a ax=-15.0 m. part a: what is the y-component of vector a? part b: what is the magnitude of vector a?

a)  Y component of the vector =15.54 m

b) Vector magnitude = 21.6 m

Explanation:

The given vector makes 44 degree angle with Y axis, as given. This is same as 90 -44 = 46 degrees with the horizontal or X axis.

b) X component of the given vector = = A cos 46 =15

⇒ A = 15/cos 16 = 21.6 m = Total vector magnitude.

a) Y component of the vector = 21.6 sin 46 = 15.54 m

b) A = 21.6 m

not too sure thinking all accelerations are pointed down