In a game of basketball, a forward makes a bounce pass to the center. the ball is thrown with an initial speed of 4.4 m/s at an angle of 24° above the horizontal. it is released 0.70 m above the floor. q1: what horizontal distance does the ball cover before bouncing? show how to solve for t in the problem.

The horizontal distance is 2.41 mts

Explanation:

For this problem, we will use the formulas of parabolic motion.

We need to find the time of the whole movement (t), for that we will use the first formula:

we need the initial velocity for that:

so:

now we have a quadratic function, solving this we obtain two values of time:

t1=0.60sec

t2=-0.234sec

the obvious value is 0.60sec, we cannot use a negative time.

Now we are focusing on finding the horizontal distance.

the movement on X is a constant velocity motion, so:

so:

the answer would be 32*f

the area between the graph and the t axis