Awindow washer drops a brush from a scaffold on a tall office building. what is the speed of the falling brush after 3.28 s? (neglect drag forces.) the acceleration due to gravity is 9.8 m/s^2. answer in units of m/s.

The speed of washer will be 32.144 m/s

Explanation:

Given that

time t= 3.28 s

Acceleration due to gravity

Here acceleration  is constant so we cam apply the motion equation

we know that

v= u + at

At initial condition  u =0 m/s

v= u + at

v= 0 + 9.8 x 3.28

v= 32.144 m/s

So the speed of washer will be 32.144 m/s

a=d/t

a="triangle"v/t

explanation:

a = acceleration