You push your textbook 1.5 m along a horizontal tabletop with a horizontal push of 2.4 n while the opposing force of friction is 0.6 n. what is the net work done on the book?

2.7 J

Explanation:

Firstly calculate the resultant force...,

; Resultant force = 2.4 - 0.6

= 1.8 N

; Hence net work done = Resultant force × Distance moved by the body

; Net work done = 1.8 × 1.5

; Net work done = 2.7 J

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pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y