What slit width is needed to produce a central maximum 15° wide for 600 nm light undergoing single slit diffraction?

The slit width is 2.31 μm

Explanation:

Given  that

Angle θ = 15°

Wavelength λ = 600 nm

We know  that  relationship  between slit  width and  wavelength

Now  by putting the  values

w=2318.22 nm

w= 2.31 μm

So the slit width is 2.31 μm

object 2 because all the other ones are wrong

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.