Adisk between vertebrae in the spine is subjected to a shearing force of 425 n. find its shear deformation, taking it to have a shear modulus of 1.70×10^9 n/m^2. the disk is equivalent to a solid cylinder 0.700 cm high and 6.50 cm in diameter. a) 5.27 x 10^-7 m
b) 1.54 x 10^-6 m
c) 3.08 x 10^-6 m
d) 6.16 x 10^-6 m

option A

Explanation:

given,

shear force = 425 N

Shear modulus = 1.7 × 10⁹ N/m²

disk equivalent to solid cylinder

height = 0.7 cm  and diameter = 6.50 cm

hence, the correct answer is option A

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