Car 1 is 200 m ahead of car 2 on the highway. car 1 is going 80 kph and car 2 is going 60 kph. car 2 decides to accelerate at a rate of 1 m/s2 until he catches up. how long will it take to catch up? what will be the car’s final velocity?

It will take 26.32 seconds to catch up, and the Car 2 final velocity is 42.98 m/s (or 154,73 km/h)

Explanation:

We have that the Car 1 initial position is X1(0)=200 m, and the Car 2 initial position is X2(0)=0 m. The Car 1 initial speed is V1(0)=80 km/h and Car 2 initial speed is V2(0)=60 km/h. Using the fact that 1 h = 3600 s and 1 km = 1000 m, we have that V1(0)=22.22 m/s (I suggest you always use the International Units System, meters, seconds, Kilograms). Now we can write the equations:

The catch up happens when X1(t)=X2(t):

Solving the cuadratic equation we have that t1= -15.2 s and t2=26.32 s. The correct answer of course is t is time, so we have that in 26.32 s the Car 2 catches up Car 1.

Now using this time we find

Or 154.73 km/h.

report!

explanation:

physics means: "the branch of science concerned with the nature and properties of matter and energy. the subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms."

im srry but ur wrong the answer is d a smooth rock, some red dirt, and an empty bird's nest.