2/24 at what angle θ must the 400-lb force be applied in order that the resultant r of the two forces have a magnitude of 1000 lb? for this condition what will be the angle β between r and the horizontal?

θ=66.42°

β=23.5781°

Explanation:

component in y: Ry = 400 Lb

Resultant = R  = 1000 Lb

to calculate the angle θ we use the cosine function

cosθ=400/100

θ=arccos(400/100)=66.42°

remember that the angles of internal of a triangle measure 180 degrees

β =180°-66.42°-90°( right angle)

β=23.5781°

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