During a takeoff run, an aircraft starts from rest and has a lift-off speed of 120 km/h. a. what minimum constant acceleration does the aircraft require if the aircraft is to be airborne after a takeoff run of 280 m?

1.984 m/s^2

Explanation:

initial velocity of air craft, u = 0 m/s

final speed of the aircraft, v = 120 km/h

Convert the speed into m/s from km/h

So, v = 120 km/h = 33.33 m/s

distance, s = 280 m  

Let a be the acceleration of the aircraft.

Use third equation of motion

a = 1.984 m/s^2

Thus, the acceleration of the aircraft is 1.984 m/s^2.

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