A11.8-gram sample of zinc is heated to 98.15°c in a boiling water bath. the hot metal is then immersed in 25.35 grams of water that is initially at 21.82°c. at what temperature will the metal and the water reach thermal equilibrium? the specific heat of zinc is 0.388 j/g·°c. the specific heat of water is 4.184 j/g·°c.

T =24.98 °C

Explanation:

from equilibrium condition we have:

[m_1*s*T]_{water} = [m_2*s*T]_{zinc}

Where

m_1 , m_2 is mass of water and zinc respectively

s denote specific heat

let final equilibrium temperature is T

25.35*4.184*[T-21.82] = 11.8*0.388*[98.15-T]

106.06T - 2314.32 = 449.36 - 4.57T

110.63 T =  2763.68

T =24.98 °C

luster is not a good characteristic to use by itself because luster is the property of minerals that indicates how much the surface of a mineral reflects light. the luster of a mineral is affected by the brilliance of the light used to observe the mineral surface.