The force f of magnitude 100 lb is to be resolved into two components along the lines a-a and b-b. determine by trigonometry the angle a, knowing that the component of f along line a-a is 40 lb\

θ=66.42°

Explanation:

Given that

F= 100 lb

The force along a-a is 40 lb

Lets take θ is the angle made by force F from a-a

So the component of force F along a-a will F cosθ and the component of force along b-b is F sinθ.

The force along a-a given that 40 lb,so we can say that

  F cosθ= 40

  100  cosθ = 40

cosθ= 0.4

θ=66.42°

The angle from a-a is 66.42°.

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