A60-gallon water heater is initially filled with water at 66°f. determine how much energy, in btu, needs to be transferred to the water to raise its temperature to 104°f. given: the water properties at an average water temperature of 85ºf rho = 62.17 lbm/ft3 and cp = 0.999 btu/lbm-r.

18930 Btu

Explanation:

The amount of heat needed to raise the temperature of a body of water is given by:

Q = m * cp * (tfin - ti)

The mass is the volume multiplied by the density

m = V * ρ

So

Q = V * ρ * cp * (tfin - ti)

The volume of water is 60 gallon, which is equivalent to 8.021 ft^3

Now:

Q = 8.021 ft^3 * 62.17 lbm/(ft^3) * 0.999 Btu/(lbm * R)* (104 R - 66 R) = 18930 Btu

Since we have a temperature difference we can convert Fahrenheit to Rankine

does anyone know or what?

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .