Agas is contained in a vertical, frictionless piston–cylinder device. the piston has a mass of 3.2 kg and a cross-sectional area of 35 cm2. a compressed spring above the piston exerts a force of 110 n on the piston. if the atmospheric pressure is 95 kpa, determine the pressure inside the cylinder.

146.826 KPa

Explanation:

Given:

The mass of the piston = 3.2 kg

Cross-sectional area = 35 cm²

Force exerted by the spring = 110 N

Atmospheric pressure = 95 KPa

Now,

the total pressure inside the cylinder is the sum of all the pressure exerted on it i,e the pressure due the weight of the piston, pressure due to the force by the spring and the atmospheric pressure.

Now,

the pressure due to the weight of the piston = Weight / Area

= 3.2× 9.81 / 0.0035

= 31.392 / 0.0035

= 8969 Pa

= 8.969 KPa

And,

The pressure by the spring = 150 N / 0.0035

or

The pressure by the spring = 42,857 Pa = 42.857 KPa

Thus,

The total pressure

95 + 8.969 + 42.857 = 146.826 KPa

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y