What current flow (i) is associated with an input voltage of 8.0v and resistors r1 = 2.5 kiloohms and r2 = 3.5 kiloohms? calculate this value in ma

current in series is 1.33 mA

current in parallel is 5.48 mA

Explanation:

given data

voltage = 8 V

resistors R1 = 2.5 kilo ohms

resistors R2 = 3.5 kilo ohms

to given data

current flow

solution

current flow in series is express as

current = voltage / resistor

put here all value

current = 8 / (2.5 + 3.5)

current = 8 / 6

current = 1.33 mA

and

current flow in parallel is express as

current = voltage / resistor

put here all value

current = 8 / (1/ (1/2.5 + 1/3.5))

current = 8 / 1.45

current = 5.48 mA

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