Calculate minimum number of incident photons per area and of the minimum dose needed to visualize an object of 1 mm squared using x rays of energy 50 kev. ( thickness 10^-3)(contrast 1%)

minimum number of photon is 4.05 ×

Explanation:

given data

energy = 50 keV = 50 × eV =  50 × × 1.602×  J

thickness = 10^-3

contrast = 1%

to find out

number of incident photons

solution

we know here equation that is

E  = n  × h  × ν   .......................1

put here all these value

50 × = n × 6.6× × c/ 1×

50 × × 1.602×  = n × 6.6× ×( 3 × / 1× )

solve it and find n

n = 4.05 ×

so here minimum number of photon is 4.05 ×

adding a(n) to an electric circuit would increase the magnetic field around a wire;

b. solenoid

a solenoid is a type of electromagnet whose purpose is to generate a controlled magnetic field.

if the purpose of the solenoid is instead to impede changes in the electric current, a solenoid can be more specifically classified as an inductor rather than an electromagnet.