We consider a gas in thermal equilibrium with a reservoir. if a piston does a certain amount of work on the gas w very slowly (isothermal compression), how does s change for the gas? s should decrease right? using s = q/t, the system loses q and therefore s should decrease. but doesn't a system always increase in entropy?

The entropy of the gas increases

Explanation:

The entropy of an isolated system tends to increase. but this gas gas is not isolated. It has a piston perfoming work on it and it can exchange heat with it's surroundings.

While the system's entropy decreases, the surroundings' entropy increases, and the entropy change of the universe, which is the sum of the entropy changes of the system and the surroundings, will be equal or greater than zero.

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong

where is the circuit diagram ?