A85.0 cm wire of mass 9.40 g is tied at both ends and adjusted to a tension of 39.0 n . when it is vibrating in its second overtone, find the frequency at which it is vibrating. when it is vibrating in its second overtone, find the frequency of the sound waves it is producing. when it is vibrating in its second overtone, find the wavelength of the sound waves it is producing.

frequency = 104.80 Hz

wavelength = 0.567 m

frequency = 104.80 Hz

wavelength = 3.27 m

Explanation:

given data

mass m = 9.4 g = 9.4 × m

length L = 85 cm = 0.85 m

tension  T = 39 N

to find out

frequency and wavelength

solution

first we find frequency for second overtone

f = 3 /2L × √(T/μ)   .............1

put here all value and

here μ = m/L = 9.4 × / 0.85 = 1.10588 × kg/m

f = 3 /2(0.85) × √(39/1.10588 ×)

f = 104.80 Hz

and

wavelength is 2L/3

wavelength = 2(0.85) / 3

wavelength = 0.567 m

and

frequency = 104.80 Hz

and

wavelength by speed of sound i.e 343 m/s

wavelength = speed / f

wavelength = 343 / 104.80

wavelength = 3.27 m

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min