A100 a current circulates around a 1.60-mm-diameter superconducting ring. what is the on-axis magnetic field strength 5.40 cm from the ring? express your answer with the appropriate units.

magnetic field  is 2.55 × T

Explanation:

given data

current = 100 A

diameter = 1.60 mm

strength = 5.40 cm

to find out

What is the on-axis magnetic field

solution

we know here magnetic field on x axis current carry circular loop so it will

B = u / 4π × 2π R² I /    ...............1

here I is current and  r is radius and x distance  

so

B = 4π × /  4π × 2π (1.60× 10^-3 / 2 )² (100) /

solve it and we get B

B =  2.55 × T

magnetic field  is 2.55 × T