Asmall region of space in the shape of a cube of side 1 mm, contains 10.0 j of energy in the form of an electric field. calculate the magnitude of the electric field (vm-1)

electric field is 4.75  ×  V/m

Explanation:

given data

cube of side = 1 mm

energy = 10 J

to find out

magnitude of the electric field

solution

to find electric field

we will apply here energy formula that is

energy  = 1/2 × ∈ × E² × volume   ...............1

here  we know ∈ = 8.85 ×

so put all value to get E electric field

energy  = 1/2 × ∈ × E² × volume

10  = 1/2 × 8.85 ×  × E² × (1/1000)³

solve it and get E

E² = 2× 10 / 8.85 ×  × (1/1000)³

E = 4.75  ×

so  electric field is 4.75  ×  V/m

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.