If the rate of energy loss for a 2.5 mev proton in graphite of density 2.25 102 kg/m is 32.3 gev/m, estimate the rate of energy loss in gaseous nitrogen of density 1.29 kg/m?

185.18 meV/m

Explanation:

Energy loss for charge particle is given by

\frac{\mathrm{d} E}{\mathrm{d} x}\propto \frac{\rho Zz^2}{A}

where

\frac{\mathrm{d} E}{\mathrm{d} x} Energy loss per unit length

\rho density

Z atomic number

A atomic mass

z charge of incident particle(for proton it is 1)

For graphite

Z=6

A=12

For gaseous nitrogen

Z=7

A=14

For graphite

Divide 1 and 2

E'=185.18 MeV/m

there are no correct statementd on the list of choices you provided.

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.