Suppose you spray your sister with water from a garden hose. the water is supplied to the hose at a rate of 0.433×10−3 m3/s0.433×10−3 m3/s and the diameter of the nozzle you hold is 5.855.85 × 10-3 m. at what speed does the water exit the nozzle

m/s

Explanation:

 = Volume flow rate of water through the hose = 0.433 x 10⁻³ m³

= diameter of nozzle = 5.85 x 10⁻³ m

Area of cross-section of nozzle is given as

m²

= speed of water exiting the nozzle

Using equation of continuity

m/s

the amount of current in the coil

no sign of dia of fuel cell