Show that if the net force on a particle constrained to move in 1 dimension depends only on position, f-f), the newton's second law can be solved to find v as a function ofx given by: 1 dv2 2 dx v2-si +副0f(x')dx'. note: use the chain rule: dt- = 2dte b) consider a mass constrained to move along x-axis and subject to a net force f =-kx, where k > 0 is a constant. the mass is released form rest at x xo at t-0. use the equation for velocity from part a) to find (x) = . separate the variables and integrate to obtain the time dependence of the position of this mass. hint: when solving the awkward integral you will obtain, use first the suband then ucos 0 in subsequent integral. dt dx dt dx