A50-kg load is suspended from a steel wire of diameter 1.0 mm and length 11.2 m. by what distance will the wire stretch? young's modulus for steel is 2.0 x 1011 pa.
show work.

3.5 cm

Explanation:

mass, m = 50 kg

diameter = 1 mm

radius, r = half of diameter = 0.5 mm = 0.5 x 10^-3 m

L = 11.2 m

Y = 2 x 10^11 Pa

Area of crossection of wire = π r² = 3.14 x 0.5 x 10^-3 x 0.5 x 10^-3  

                                              = 7.85 x 10^-7 m^2

Let the wire is stretch by ΔL.

The formula for Young's modulus is given by

ΔL = 0.035 m = 3.5 cm

Thus, the length of the wire stretch by 3.5 cm.

he kicked it 10 feet straight up into the air? i think this works.

i think the answer is a, hope this is right, that would be my best guess.