500 j of heat is added to the gas in an isothermal process. as the gas expands, pushing against the piston, how much work does it do?

500 J

Explanation:

The isothermal process is the process in which the temperature is constant in the entire process.

As we know that the change in internal energy is the function of change in temperature. here temperature is constant so there in no change in internal energy.

So, By the First law of thermodynamics

ΔQ = ΔU + ΔW

Here, ΔQ is heat added and ΔU be the change in internal energy and ΔW be the work done

Here, ΔU = 0

So, ΔW = ΔQ = 500 J

So, the work done is 500 J.

that would be b i just took the test : )

c. newton's third law of motion