What is the linear separation d at the retina (micrometers)? the minimum diameter of the pupil is about 2 mm, the eye is most sensitive to wavelengths of about 500 nm (air), the index of refraction of the aqueous humor is n = 1.33, and the distance between the cornea and retina is about 2.5 cm.

The linear separation at the retina is

Explanation:

Given that,

Minimum diameter of the pupil = 2 mm

Wavelength = 500 nm

Index of refraction = 1.33

Distance between the cornea and retina = 2.5 cm

We need to calculate the angular separation

Using formula of angular separation

We need to calculate the linear separation at the retina

Using formula of linear separation

Put the value into the formula

Hence, The linear separation at the retina is .

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

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