Apot of water is boiling under one atmosphere of pressure. assume that heat enters the pot only through its bottom, which is copper and rests on a heating element. in two minutes, the mass of water boiled away is m = 4.5 kg. the radius of the pot bottom is r = 6.5 cm and the thickness is l = 2.0 mm. what is the temperature of the heating element in contact with the pot?

Explanation:

It is given that,

Mass of boiled water, m = 4.5 kg

Radius of the pot bottom, r = 6.5 cm = 0.065 m

Thickness of the pot, t = 2 mm = 0.002 m

We need to find the temperature of the heating element in contact with the pot.

Heat transferred is from pot to water is given by :

T₁ is the boiling temperature of water, T₁ = 100⁰ C

, q = m L, L is the latent heat of vaporization

,

k is the thermal conductivity of water,

Hence, this is the required solution.

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