When the hydraulic conductivity ks = 10 mm/hr; effective matrix potential ns = 20 mm, and rainfall intensity i = 30 mm/hr , determine the amount of runoff generated when the runoff rate reaches 15 mm/hr? ( 2.7 mm or 0.21 mm or 18 mm or 0.67 mm)

If the heat engine is a perfect carnot cycle engine, thenefficiency = (t2-t1)/t2   where t1=temperature of cold reservoir ( ° k) = 135            t2=temperature of hot reservoir ( ° k)   = 325thereforeefficiency = (t2-t1)/t2 = (325-135)/325 = 0.5846 = 58%  note: this is the theoretical maximum efficiency of a perfect heat engine.   real-life engines do not achieve this value.

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