Each of the two coils has 320 turns. the average radius of the coil is 6 cm. the distance from the center of one coil to the electron beam is 3 cm. if a current of 0.5 amperes runs through the coils, what is the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils

Magnetic field,

Explanation:

It is given that,

Number of turns, N = 320

Radius of the coil, r = 6 cm = 0.06 m

The distance from the center of one coil to the electron beam is 3 cm, x = 3 cm = 0.03 m

Current flowing through the coils, I = 0.5 A

We need to find the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils. The magnetic field midway between the coils is given by :

B = 0.00239 T

or

So, the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils is . Hence, this is the required solution.

the answer would be 32*f