Abattery does 2.186 j of work to transfer 0.033 c of charge from the negative to the positive terminal. what is the emf of this battery?

66.24 Volts

Explanation:

W = Amount of work done in moving the charge from negative to positive terminal = 2.186 J

Q = Amount of charge being moved from negative to positive charge = 0.033 C

ΔV = EMF of the battery

Amount of work done in moving the charge from negative to positive terminal is given as

W = Q ΔV

2.186 = (0.033) ΔV

ΔV = 66.24 Volts

if the thermos has a vacuum innner, then heat through conv currents and conduction are reduced = vacuum flask

12000j is work done