Two adjacent natural frequencies of an organ pipe are amt determined to be 550 hz and 650 hz. calculate (a) the m fundamental frequency and (b) the length of this pipe.

The fundamental frequency and length of the pipe are 100 Hz and 1.7 m.

Explanation:

Given that,

Frequency f = 550 Hz

Frequency f' = 650 Hz

We know that,

AMT pipe is open pipe.

(b). We need to calculate the length of the pipe

Using formula of organ pipe

For 550 Hz,

...(I)

For 650 Hz,

...(II)

From equation (I) and (II)

(a). We need to calculate the fundamental frequency for n = 1

Using formula of  fundamental frequency

put the value of L

Hence, The fundamental frequency and length of the pipe are 100 Hz and 1.7 m.

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.