The gauge pressure in your car tires is 2.20 x 10^5 n/m^2 at a temperature of 35.0°c when you drive it onto a ferry boat to alaska. what is their gauge pressure (in atm) later, when their temperature has dropped to −38.0°c? (assume that their volume has not changed.)

1.425 atm

Explanation:

Gauge pressure, P1' = 2.20 x 10^5 N/m^2 = 2.178 atm

Absolute pressure P1 = P1' + Po

where, Po be the atmospheric pressure

P1 = 2.178 + 1 = 3.178 atm

T1 = 35 degree C = 35 + 273 = 308 k

T2 = - 38 degree c = - 38 + 273 = 235 k

let final absolute pressure is P2.  Use

P1 / T1 = P2 / T2

3.178 / 308 = P2 / 235

P2 = 2.425 atm

So, the final gauge pressure = 2.425 - 1 = 1.425 atm

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.