Find the kinetic energy ofan electron that moves at half the speed of light to four significant digits.

Ke=electron kinetic energy=

Explanation:

The electron has a mass of

The speed of light in a vacuum is a universal constant with the value 299 792 458 m / s (186 282,397 miles / s), although it is usually close to

Kinetic energy (K) is the energy associated with bodies that are in motion, depends on the mass and speed of the body and is calculated using the formula:

       Equation(1)

K=kinetic energy (J)

m =mass of the body (kg)

v= speed of the body

for this problem We replace in the equation (1)

= electron mass

=Half the speed of light

=electron speed

We replace in  the  equation (1) :

The energy kinetic of the electron is

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this