The third-order bright fringe of 610-nm light is observed at an angle of 31° when the light falls on two narrow slits. how far apart are the slits?

The distance between the slits is 3.55 μm

Explanation:

Given that,

Order number = 3

Wave length = 610 nm

Angle = 31°

We need to calculate the distance between the slits

Using formula of distance of slit

Where, n = order number

= wavelength

Put the value into the formula

Hence, The distance between the slits is 3.55 μm.

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )