At a distance of 3.5 cm from the center of a very long uniformly charged wire, the electric field has magnitude 2000 n/c and is directed toward the wire. what is the charge on a 1.0 cm length of wire near the center?

The electric field strength from a very long (essentially infinitely long) uniformly charged wire is given by:

E = λ/(2πrε₀)

E = electric field strength, λ = linear charge density, r = distance from wire

Given values:

E = 2000N/C, r = 3.5×10⁻²m

Plug in and solve for λ:

2000 = λ/(2π(3.5×10⁻²)(8.85×10⁻¹²))

λ = 3.9×10⁻⁹C/m

The amount of charge on a certain length of this wire is given by:

Q = λL

Q = charge, λ = charge density, L = length

Given values:

λ = 3.9×10⁻⁹C/m, L = 1.0×10⁻²m

Plug in and solve for Q:

Q = 3.9×10⁻⁹(1.0×10⁻²)

Q = 3.9×10⁻¹¹C

emily ruth's annual premium is $1058.50

step-by-step explanation:

emily ruth is a female of 27 years age purchasing 20 year endowment insurance with face value $25000.

from the given table,

for females, the age of a male 3 years younger should be used.

so, we have to check for 24 year male for 20 year endowment.

it is 42.34 for every $1000 face value.

for a face value of $25000,

it is 25 * 42.34 = $1058.50

∴ emily ruth's annual premium is $1058.50