Work-energy theorem: a 4.0 kg object is moving with speed 2.0 m/s. a 1.0 kg object is moving with speed 4.0 m/s. both objects encounter the same constant braking force, and are brought to rest. which object travels the greater distance before stopping?

The same braking force does work on these objects to slow them down. The work done is equal to their change in kinetic energy:

FΔx = 0.5mv²

F = force, Δx = distance traveled, m = mass, v = speed

Isolate Δx:

Δx = 0.5mv²/F

Calculate Δx for each object.

Object 1: m = 4.0kg, v = 2.0m/s

Δx = 0.5(4.0)(2.0)²/F = 8/F

Object 2: m = 1.0kg, v = 4.0m/s

Δx = 0.5(1.0)(4.0)²/F = 8/F

The two objects travel the same distance before stopping.

a and b sometimes have a positive value