The fusion reaction 2h + 2h --> 3he + n releases energy 3.27 mev per decay. how long could the fusion of 1.0 kg of this hydrogen isotope by this reaction keep a 100 w lamp burning?

time taken is  2.49  x year

Explanation:

Given data

energy = 3.27 MeV

mass = 1 kg

to find out

time period

solution

we know  that deuterium atomic mass unit = 1.66053886 x kg

and we know that energy release = 1 kg × 3.27 / 2×2×1.66053886 x

energy release = 4.9231 x MeV

energy release  = 4.9231 x  × 1.6 x  = 7.87 x  J

so at 100 W

energy = power × time

time = 7.87 x  / 100

time = 7.87 x s = 7.87 x  /  3.15 x =  2.49  x year

so time taken is  2.49  x year

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.