The range of human hearing is roughly from twenty hertz to twenty kilohertz. based on these limits and a value of 343 m/s for the speed of sound, what are the lengths of the longest and shortest pipes (open at both ends and producing sound at their fundamental frequencies) that you expect to find in a pipe organ?

Explanation:

It is given that, the range of human hearing is roughly from twenty hertz to twenty kilohertz.

Minimum frequency, f = 20 Hz

Maximum frequency, f' = 20,000 Hz

We need to find the lengths of the longest and shortest pipes. For open pipes, the length of pipe is given by :

For shortest pipe, frequency should be maximum,

l = 0.008575 m

For longest pipe, frequency should be minimum,

l' = 8.575 m

So, the lengths of longest and shortest pipes are 8.575 meters and 0.008575 meters respectively.

568.98

explanation:

its math

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.