Aturntable spins up from rest with an angular acceleration of 1.0 rad/s2. a rubber eraser of mass 20 g with coefficientof static friction 1.0 is at a distance of 0.1 m from the center of the turntable, when it begins to spin. how long does ittake for the eraser to begin to slide off the turntable? note that the tangential acceleration of the eraser is very small.

9.89 seconds

Explanation:

Angular acceleration, α = 1 rad/s^2

mass of eraser, m = 20 g

μ = 1

r = 0.1 m

here, the centripetal force is balanced by the frictional force

m x r x ω^2 = μ m x g

r x ω^2 = μ g

ω^2 = 1 x 9.8 / 0.1 = 98

ω = 9.89 rad/s

Here, ωo = 0

Use

ω = ωo + α x t

9.89 = 0 + 1 x t

t = 9.89 seconds

when cloud cover increases then the suns ray's which provides the earth with light and warmth gets covered due to the due to the suns ray's being blocked, the temperature in that region

therefore to conclude i would like to say that,

=more the cloud cover, the lesser the

happy to

pls mark as brainliest.

answer: a. same unit

explanation: