Acircular loop of radius 11.7 cm is placed in a uniform magnetic field. (a) if the field is directed perpendicular to the plane of the loop and the magnetic flux through the loop is 8.60 10-3 t · m2, what is the strength of the magnetic field?

Magnetic field, B = 0.199 T

Explanation:

It is given that,

Radius of circular loop, r = 11.7 cm = 0.117 m

Magnetic flux through the loop,

The magnetic flux linked through the loop is :

Here,

or

B = 0.199 T

So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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